× Please submit new Bug Reports on GitHub: github.com/Jensen-Technologies/component-creator-issues/issues

Show on list view no longer working correctly

7 Jahre 10 Monate her #1470 von alex
I have a field J_SQL

It is a select of virtuemart products.

On the list view it always has shown the "selected" product. ie the value in the database.

Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
Anhänge:

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

7 Jahre 10 Monate her - 7 Jahre 10 Monate her #1471 von Andres Maeso
Andres Maeso antwortete auf Show on list view no longer working correctly
Hi Alex,

Just wanted to remind you that this is a community forum where users give advice to each other. As a premium user you can send a support ticket www.component-creator.com/en/help/contact and our developers will give you some tips.

Regards,

Andrés.

Andrés Maeso
Customer relations manager at Joomla Component Creator.

Diese E-Mail-Adresse ist vor Spambots geschützt! Zur Anzeige muss JavaScript eingeschaltet sein!
Letzte Änderung: 7 Jahre 10 Monate her von Andres Maeso.

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

7 Jahre 9 Monate her #1484 von Chris
I see same problem. I checked my database, data is saving correctly, but showing incorrectly on admin list view.

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

7 Jahre 9 Monate her #1485 von Chris
I was able to adjust the query in the list model, adding a left join, grabbing the correct data. Then I edited the view file, showing the "name" rather than the "id" of the field in question. This challenged my SQL skills, but solved the problem.

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

7 Jahre 9 Monate her #1487 von alex
so how did you solve this?

can you post it here?

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

7 Jahre 9 Monate her #1490 von Chris
Alex, Something like this...

let's say you have "items" and "parents". You want to show a list of items with the correct parent name.

Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.

Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.

Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.

I had to brush up on MySql joins as well as the JDatabase query() object.

As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.

As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.

That's as specific as I can explain, hope it helps.
Folgende Benutzer bedankten sich: Andres Maeso

Bitte Anmelden oder Registrieren um der Konversation beizutreten.

Ladezeit der Seite: 0.064 Sekunden
Powered by Kunena Forum

Wir verwenden eigene Cookies und Cookies von Drittanbietern, um Ihr Nutzererlebnis zu verbessern und Ihnen einen optimalen Service zu bieten. Wenn Sie die Website weiter nutzen, gehen wir davon aus, dass Sie mit unserer Cookie-Politik einverstanden sind.